{"id":753,"date":"2016-07-30T20:00:42","date_gmt":"2016-07-30T13:00:42","guid":{"rendered":"http:\/\/apanano.com\/?p=753"},"modified":"2023-02-24T17:15:34","modified_gmt":"2023-02-24T10:15:34","slug":"tieu-chuan-chon-tom-su-giong","status":"publish","type":"post","link":"https:\/\/apanano.vn\/vi\/technical-support\/aquaculture\/tieu-chuan-chon-tom-su-giong\/","title":{"rendered":"Ti\u00eau chu\u1ea9n ch\u1ecdn t\u00f4m s\u00fa gi\u1ed1ng"},"content":{"rendered":"

Ch\u1ecdn gi\u1ed1ng t\u1ed1t, \u0111\u1ea1t ti\u00eau chu\u1ea9n l\u00e0 m\u1ed9t trong nh\u1eefng y\u1ebfu t\u1ed1 quan tr\u1ecdng g\u00f3p ph\u1ea7n t\u0103ng s\u1ea3n l\u01b0\u1ee3ng thu ho\u1ea1ch v\u00e0 ph\u00f2ng ng\u1eeba b\u1ec7nh trong qu\u00e1 tr\u00ecnh nu\u00f4i t\u00f4m.<\/strong><\/em><\/p><\/blockquote>\n

KHUNG L\u1ecaCH M\u00d9A V\u1ee4 TH\u1ea2 GI\u1ed0NG NU\u00d4I T\u00d4M N\u01af\u1edaC L\u1ee2 2024<\/strong><\/a><\/h3>\n

Ti\u00eau chu\u1ea9n l\u1ef1a ch\u1ecdn:<\/strong>
\n– Con gi\u1ed1ng ph\u1ea3i \u0111\u1ed3ng \u0111\u1ec1u, c\u00f9ng k\u00edch c\u1ee1, kho\u1ea3ng 12mm.
\n– T\u00f4m s\u00fa c\u00f3 6 \u0111\u1ed1t \u1edf b\u1ee5ng, c\u00e1c \u0111\u1ed1t n\u00e0y c\u00e0ng d\u00e0i c\u00e0ng t\u1ed1t v\u00e0 t\u00f4m s\u1ebd l\u1edbn nhanh. T\u00f4m c\u00f3 \u0111u\u00f4i, r\u00e2u h\u00ecnh d\u00e1ng ch\u1eef V v\u00e0 g\u00f3c hai r\u00e2u s\u00e1t nhau nh\u01b0 g\u00f3c ch\u1eef V l\u00e0 t\u00f4m kho\u1ebb.
\n– C\u00e1c ch\u00e2n \u1edf ph\u1ea7n \u0111u\u00f4i g\u1ecdi l\u00e0 ch\u00e2n \u0111u\u00f4i hay \u0111u\u00f4i, khi b\u01a1i xo\u00e8 r\u1ed9ng, kho\u1ea3ng c\u00e1ch gi\u1eefa 4 ch\u00e2n \u1edf ph\u1ea7n \u0111u\u00f4i c\u00e0ng xa c\u00e0ng t\u1ed1t…
\n– C\u01a1 th\u1ecbt b\u1ee5ng t\u00f4m co \u0111\u1ec1u \u0111\u1eb7n, c\u0103ng b\u00f3ng m\u1edbi t\u1ea1o \u0111\u01b0\u1ee3c d\u00e1ng v\u1ebb \u0111\u1eb9p cho t\u00f4m.
\n– Kh\u00f4ng c\u00f3 v\u1eadt l\u1ea1 nh\u01b0 n\u1ea5m, vi khu\u1ea9n, hay nguy\u00ean sinh \u0111\u1ed9ng v\u1eadt b\u00e1m \u1edf ch\u00e2n, b\u1ee5ng, \u0111u\u00f4i, v\u1ecf v\u00e0 mang t\u00f4m. Nh\u1eefng v\u1eadt l\u1ea1 n\u00e0y s\u1ebd l\u00e0m t\u00f4m b\u1ecb ng\u1ea1t v\u00e0 kh\u00f4ng l\u1ed9t x\u00e1c \u0111\u01b0\u1ee3c.<\/p>\n

\"Ti\u00eau
Ti\u00eau chu\u1ea9n ch\u1ecdn t\u00f4m s\u00fa gi\u1ed1ng<\/em><\/figcaption><\/figure>\n

– M\u00e0u s\u1eafc t\u00f4m t\u01b0\u01a1i s\u00e1ng, v\u1ecf m\u1ecfng, c\u00f3 m\u00e0u tro \u0111en \u0111\u1ebfn \u0111en, \u0111\u1ea7u th\u00e2n c\u00e2n \u0111\u1ed1i l\u00e0 con gi\u1ed1ng t\u1ed1t.
\n– T\u00f4m b\u01a1i ng\u01b0\u1ee3c d\u00f2ng r\u1ea5t kho\u1ebb khi \u0111\u1ea3o n\u01b0\u1edbc trong ch\u1eadu ho\u1eb7c b\u00e1m ch\u1eafc khi b\u1ecb d\u00f2ng n\u01b0\u1edbc cu\u1ed1n \u0111i. N\u1ebfu c\u00f3 10 trong s\u1ed1 200 con th\u1ea3 m\u00e0 tr\u00f4i theo d\u00f2ng n\u01b0\u1edbc l\u00e0 gi\u1ed1ng t\u00f4m y\u1ebfu, t\u00f4m x\u1ea5u. T\u00f4m ph\u00e0m \u0103n, \u0103n t\u1ea1p, ch\u00e2n ng\u1ef1c b\u1eaft gi\u1eef m\u1ed3i t\u1ed1t l\u00e0 con gi\u1ed1ng t\u1ed1t.
\n– T\u00f4m c\u00f3 kh\u1ea3 n\u0103ng ch\u1ecbu \u0111\u1ef1ng t\u1ed1t khi d\u00f9ng formol. S\u1ed1 t\u00f4m b\u1ecb ch\u1ebft \u00edt (5\/150 con) khi d\u00f9ng formol 1cc\/10 l\u00edt n\u01b0\u1edbc, \u0111\u00f3 l\u00e0 gi\u1ed1ng t\u1ed1t.
\nSau khi ch\u1ecdn l\u1ef1a t\u00f4m gi\u1ed1ng theo c\u00e1c ti\u00eau chu\u1ea9n tr\u00ean, tr\u01b0\u1edbc khi th\u1ea3 t\u00f4m v\u00e0o ao, ph\u1ea3i t\u1eafm v\u00f4 tr\u00f9ng cho t\u00f4m r\u1ed3i th\u1ea3 t\u00f4m gi\u1ed1ng v\u00e0o ao ho\u1eb7c \u01b0\u01a1ng ti\u1ebfp 15- 20 ng\u00e0y, sau \u0111\u00f3 tuy\u1ec3n ch\u1ecdn ti\u1ebfp l\u1ea7n n\u1eefa m\u1edbi th\u1ea3 nu\u00f4i s\u1ebd \u0111\u1ea3m b\u1ea3o h\u01a1n.
\nTuy\u1ec3n ch\u1ecdn l\u1ea1i nh\u1eefng con t\u00f4m kho\u1ebb, xo\u00e8 \u0111u\u00f4i ra h\u1ebft c\u1ee1 khi b\u01a1i. Nh\u1eefng con th\u00edch b\u01a1i ng\u01b0\u1ee3c d\u00f2ng n\u01b0\u1edbc th\u1ea3 v\u00e0o ao l\u00e0 t\u1ed1t nh\u1ea5t. M\u1eadt \u0111\u1ed9 th\u1ea3 trung b\u00ecnh 5- 7 con\/m2 v\u1edbi nu\u00f4i qu\u1ea3ng canh v\u00e0 30 – 50 con n\u1ebfu nu\u00f4i th\u00e2m canh.<\/p>\n

\u00a0<\/div>\r\n